What is specific heat capacity?
The energy required to raise 1 kg of a substance by 1 K. Water has a very high specific heat (4186 J/kg·K), which is why oceans moderate climate.
Specific Heat Calculator
Q = mcΔT
Calculate heat energy from mass, specific heat, and temperature change. Q = mcΔT.
Calculate
Enter values above to calculate
How it calculates
1
Q = m × c × ΔT
2
m in kg, c in J/(kg·K), ΔT in K (same as °C for differences)
3
Result Q in joules
Formula
Q = mcΔT
Variable Table
| Symbol | Quantity | SI Unit |
|---|---|---|
| Q | Heat energy | J |
| m | Mass | kg |
| c | Specific heat capacity | J/(kg·K) |
| ΔT | Temperature change | K or °C |
How to Use This Calculator
This specific heat calculator is built for quick physics checks and worked-problem review. Enter values in the units shown beside each input, then compare the result with the formula and variable table before using it in a longer solution. The calculator does the arithmetic, but the physics still depends on choosing a model that matches the situation.
Start by identifying the system, the known quantities, and the quantity you want to find. If a value is given in a non-SI unit, convert it before substitution. A correct numerical answer with mixed units can still be physically wrong, especially when squared units, inverse seconds, charges, temperatures, or distances are involved.
Assumptions and Limits
The formula Q = mcΔT is a model, not a universal description of every possible case. It assumes the quantities in the variable table are the relevant quantities for the problem and that hidden effects are either negligible or already included in the inputs. If friction, drag, relativistic speeds, changing fields, non-constant temperature, or geometry-specific effects matter, check whether a more complete model is needed.
Use the result as a magnitude and units check. Ask whether the answer has the right sign, whether it grows or shrinks when an input changes, and whether the limiting cases make sense. Setting an input to zero, doubling a quantity, or using a very large value is often enough to catch a formula choice or unit mistake before it reaches a final answer.
Worked Example
How much heat to raise 0.5 kg of water (c = 4186 J/kg·K) by 20°C?
Step 1: Q = m c ΔT
Step 2: Q = 0.5 × 4186 × 20
Answer: Q = 41,860 J ≈ 41.9 kJ
Common Mistakes
- ΔT in K = ΔT in °C for differences (but not for absolute temperature)
- Use c = 4186 J/(kg·K) for water; 900 J/(kg·K) for aluminium
- Q is positive when heat is absorbed, negative when released
Related
Frequently Asked Questions
Is ΔT in °C or K?
Either, because a difference of 1°C = a difference of 1 K. But use kelvin for absolute temperature values.