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An EMF of 10 V drives a current of 2 A through a resistor. Power dissipated is:

20 W. P = IV = 2 × 10 = 20 W. Alternatively P = I²R = V²/R.

Short Answer

20 W is the best answer.

Electromagnetism questions become manageable once you separate source, field, potential, current, and force. Most wrong answers mix those layers together or ignore direction.

P = IV = 2 × 10 = 20 W. Alternatively P = I²R = V²/R.

Why This Answer Is Correct

This is a Medium-level question in Electromagnetism. The prompt is really testing whether you can connect the concept to its defining physical relationship instead of picking a nearby-but-wrong term.

Keep charge, field, potential, and current distinct. That single habit fixes a large fraction of electromagnetism errors.

Choices At A Glance

  • A. 5 W
  • B. 12 W
  • C. 20 W
  • D. 8 W

When similar options appear on an exam, eliminate the ones that break the core law, use the wrong units, or confuse a definition with a consequence.

Topic Snapshot

Topic: Electromagnetism

Difficulty: Medium

Best next move: Re-state the governing law in your own words, then solve one more example from the same topic before moving on.