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A parallel-plate capacitor with plate separation d and area A has capacitance:

ε₀A/d. C = ε₀A/d for an ideal parallel-plate capacitor with vacuum between plates.

Short Answer

ε₀A/d is the best answer.

Electromagnetism questions become manageable once you separate source, field, potential, current, and force. Most wrong answers mix those layers together or ignore direction.

C = ε₀A/d for an ideal parallel-plate capacitor with vacuum between plates.

Why This Answer Is Correct

This is a Medium-level question in Electromagnetism. The prompt is really testing whether you can connect the concept to its defining physical relationship instead of picking a nearby-but-wrong term.

Keep charge, field, potential, and current distinct. That single habit fixes a large fraction of electromagnetism errors.

Choices At A Glance

  • A. ε₀A/d
  • B. ε₀d/A
  • C. ε₀A²/d
  • D. ε₀/Ad

When similar options appear on an exam, eliminate the ones that break the core law, use the wrong units, or confuse a definition with a consequence.

Topic Snapshot

Topic: Electromagnetism

Difficulty: Medium

Best next move: Re-state the governing law in your own words, then solve one more example from the same topic before moving on.